Optimal. Leaf size=128 \[ -\frac{5 \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )}{3 a d}+\frac{21 E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 a d}+\frac{7 \sin (c+d x) \cos ^{\frac{3}{2}}(c+d x)}{5 a d}-\frac{5 \sin (c+d x) \sqrt{\cos (c+d x)}}{3 a d}-\frac{\sin (c+d x) \cos ^{\frac{3}{2}}(c+d x)}{d (a \sec (c+d x)+a)} \]
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Rubi [A] time = 0.175728, antiderivative size = 128, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.304, Rules used = {4264, 3819, 3787, 3769, 3771, 2639, 2641} \[ -\frac{5 F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 a d}+\frac{21 E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 a d}+\frac{7 \sin (c+d x) \cos ^{\frac{3}{2}}(c+d x)}{5 a d}-\frac{5 \sin (c+d x) \sqrt{\cos (c+d x)}}{3 a d}-\frac{\sin (c+d x) \cos ^{\frac{3}{2}}(c+d x)}{d (a \sec (c+d x)+a)} \]
Antiderivative was successfully verified.
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Rule 4264
Rule 3819
Rule 3787
Rule 3769
Rule 3771
Rule 2639
Rule 2641
Rubi steps
\begin{align*} \int \frac{\cos ^{\frac{5}{2}}(c+d x)}{a+a \sec (c+d x)} \, dx &=\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sec ^{\frac{5}{2}}(c+d x) (a+a \sec (c+d x))} \, dx\\ &=-\frac{\cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}-\frac{\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{-\frac{7 a}{2}+\frac{5}{2} a \sec (c+d x)}{\sec ^{\frac{5}{2}}(c+d x)} \, dx}{a^2}\\ &=-\frac{\cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}-\frac{\left (5 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sec ^{\frac{3}{2}}(c+d x)} \, dx}{2 a}+\frac{\left (7 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sec ^{\frac{5}{2}}(c+d x)} \, dx}{2 a}\\ &=-\frac{5 \sqrt{\cos (c+d x)} \sin (c+d x)}{3 a d}+\frac{7 \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{5 a d}-\frac{\cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}-\frac{\left (5 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\sec (c+d x)} \, dx}{6 a}+\frac{\left (21 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\sec (c+d x)}} \, dx}{10 a}\\ &=-\frac{5 \sqrt{\cos (c+d x)} \sin (c+d x)}{3 a d}+\frac{7 \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{5 a d}-\frac{\cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}-\frac{5 \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{6 a}+\frac{21 \int \sqrt{\cos (c+d x)} \, dx}{10 a}\\ &=\frac{21 E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{5 a d}-\frac{5 F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 a d}-\frac{5 \sqrt{\cos (c+d x)} \sin (c+d x)}{3 a d}+\frac{7 \cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{5 a d}-\frac{\cos ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}\\ \end{align*}
Mathematica [C] time = 2.15215, size = 314, normalized size = 2.45 \[ \frac{\cos ^2\left (\frac{1}{2} (c+d x)\right ) \left (\frac{-20 \sin (c) \cos (d x)+6 \sin (2 c) \cos (2 d x)-20 \cos (c) \sin (d x)+6 \cos (2 c) \sin (2 d x)-30 \sec \left (\frac{c}{2}\right ) \sin \left (\frac{d x}{2}\right ) \sec \left (\frac{1}{2} (c+d x)\right )-96 \cot (c)-30 \csc (c)}{d \sqrt{\cos (c+d x)}}+\frac{2 i \sqrt{2} e^{-i (c+d x)} \sec (c+d x) \left (63 \left (-1+e^{2 i c}\right ) \sqrt{1+e^{2 i (c+d x)}} \text{Hypergeometric2F1}\left (-\frac{1}{4},\frac{1}{2},\frac{3}{4},-e^{2 i (c+d x)}\right )+25 \left (-1+e^{2 i c}\right ) e^{i (c+d x)} \sqrt{1+e^{2 i (c+d x)}} \text{Hypergeometric2F1}\left (\frac{1}{4},\frac{1}{2},\frac{5}{4},-e^{2 i (c+d x)}\right )+63 \left (1+e^{2 i (c+d x)}\right )\right )}{\left (-1+e^{2 i c}\right ) d \sqrt{e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )}}\right )}{15 a (\sec (c+d x)+1)} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.533, size = 229, normalized size = 1.8 \begin{align*} -{\frac{1}{15\,ad}\sqrt{ \left ( 2\, \left ( \cos \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1 \right ) \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}} \left ( -\cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \sqrt{2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}\sqrt{ \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}} \left ( 25\,{\it EllipticF} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) +63\,{\it EllipticE} \left ( \cos \left ( 1/2\,dx+c/2 \right ) ,\sqrt{2} \right ) \right ) +48\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{8}-56\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{6}-30\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{4}+23\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{2} \right ) \left ( \cos \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{-2\, \left ( \sin \left ( 1/2\,dx+c/2 \right ) \right ) ^{4}+ \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{2}}}} \left ( \sin \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{2\, \left ( \cos \left ( 1/2\,dx+c/2 \right ) \right ) ^{2}-1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{\frac{5}{2}}}{a \sec \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\cos \left (d x + c\right )^{\frac{5}{2}}}{a \sec \left (d x + c\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{\frac{5}{2}}}{a \sec \left (d x + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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